Teacher Simoonga

Good morning ladies and gentlemen.
I would like to inform you that I Mr Simoonga a science teacher will soon start offering free online lessons in physics, biology and chemistry. Please invite all school going children from grade 8 to 12 and those who are sitting for GCE sciences exams to like my page.
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WELCOME TO SCIENCE BENCH WITH TEACHER ATOM.
TONIGHT WE ARE LOOKING AT SPEED TIME GRAPH.
QUESTION.
A car start from rest and accelerate uniformly to 20m/s in 5s. And it accelerate more to 40m/s in 2s, then deccelerate until it come to rest in 5s.
(a) Draw a speed time graph
(b) Calculate the acceleration of the during its first 5s.
(c) Calculate the total distance travelled by the car.
(d) Calculate the average speed of the car.
SOLUTIONS
(a) Check the graph on the photos attached
(b) a= (V-U) / t
DATA
V = 20m/s
U = 0m/s
t = 5s
a = (20m/s - 0m/s) / 5s
a = 20m/s / 5s
a = 4m/s*
C. Total distance can be calculated by finding the total area under the graph. For that reason we are going to devid the graph into angles so that we easily find the area under the angles and then add up the areas to make total area under the graph which shall be the total distance.
Chech the photos attached.
NOW LETS CALCULATE
(A) TRIANGLE A
Area = half x Lxh
A = 0.5 x 5 x 20
A = 50M
(B) TRAPEZIUM B
Area = half x (a+b) x h
A = 0.5 x (20+40) x 2
A = 0.5 x 60 x 2
A = 0.5 x 120
A = 60M
(C) TRIANGLE C
Area = half x L x h
A = 0.5 x 5 x 40
A = 0.5 x 200
A = 100M
Total Area under the graph equals to total distance travelled.
A = 50 + 60 + 100
A = 210M
Total Distance = 210M
(c) Average speed
Av Speed = total distance / total time taken
Av Speed = 210m / 12s
Av Speed = 17.5m/s
Any question please?
Tonight Lets End Here.
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Arise and chase your dreams.

state any 2 applications of cathode ray oscilloscopes