TSHS Elite Math Circle

📆 Math Month is here, Scientians! 📣
This month invites us to celebrate Mathematics and Hope, showing that numbers and logic are more than lessons in a classroom. 🔢🌍 Mathematics helps us understand problems, find solutions, and move forward with confidence, reminding us that there is always a way to improve and progress. ✨📊

📣 To my fellow Scientians 🙌 let us take this opportunity to participate, explore, and challenge ourselves 💪📐. Every problem we solve strengthens our thinking, every equation we learn builds discipline, and every mistake teaches us perseverance. 🧠➗ Mathematics inspires hope by proving that effort, patience, and determination lead to answers.

Math Month is not only about formulas and computations 📘, but also about optimism, teamwork, and growth 🤝💡. It encourages us to think critically, believe in our abilities, and face challenges with a positive mindset. Through various activities and learning experiences, we celebrate how Mathematics equips us to build a better and brighter future 🚀📈.

I am [Name] from [Section] of Taguig Science High School 🏫, proudly joining the celebration of Math Month. 🌟 Together, let us make this month a meaningful reminder that through Mathematics and Hope, we can solve problems and create endless possibilities.

https://twb.nz/tshsmathmonth26

𝗧𝗛𝗘 𝗙𝗜𝗥𝗦𝗧 𝗢𝗡𝗘 [𝗗𝗔𝗬 𝟮] 𝗦𝗢𝗟𝗨𝗧𝗜𝗢𝗡

📍 Take note that the problem was given yesterday, January 12 2024.

In order to look for 1989 days ago yesterday, we simply just need to work backwards knowing the current day, number of days in a year (and leap years), and number of days every month.

This problem could be solved in multiple ways, and this is just a provided sample solution.

Starting with January 12, 2024, subtract 12 days to 1989 to go back at the date of December 31, 2023.

1989 – 12 = 1977

Imagine that after subtracting 12 days, we went back to date December 31, 2023 and need to look for the date 1977 days ago. The year 2023, 2022, and 2021 are ordinary years with 365 days, thus we are to subtract 3 years from 1977 days to go back at the date of December 31, 2020.

1977 – 3(365)
1977 – 1095 = 882

Now, we only need 882 days to look for. At the day December 31, 2020, the year 2020 is a leap year. In order to go back at the date of December 31, 2019, we need to subtract 366 days from the remaining 882 days.

882 – 366 = 516

On December 31, 2019, the year 2019 is a regular year with 365 days.

516 – 365 = 151

Now, it is currently December 31, 2018 and our remaining 151 days is less than a year. The only thing to do is to go back considering the days of the months.

151 – 31 days of December = 120 [November 30, 2018]
120 – 30 days of November = 90 [October 31, 2018]
90 – 31 days of October = 59 [September 30, 2018]
59 – 30 days of September = 29 [August 31, 2018]

It is currently August 31, 2018, and going back 29 days from now means 29 days subtracted from 31 days is 2. Therefore, the answer is August 2, 2018.

The day 1989 days ago yesterday is August 2, 2018!✅

Congratulations to our winner, Ziana Islam of 8 – Schwann!🥳